in a 2 digit number digit in unit place is twice the digit in tens place if 27 is added to it digits are reverse find the number
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Heya mate.....
Let us assume, x is a tenth place digit and y is the unit place digit of a two-digit number.
Therefore, the two-digit number = 10x + y and the reversed number = 10y + x
Given:
y = 2x -----------1
Also given:
10x + y + 27 = 10y + x
9y - 9x = 27
y - x = 3
Substitute the value of y from equation 1 in equation 2
2x - x = 3
x = 3
Therefore y = 2x = 2 * 3 = 6
Therefore, the two-digit number = 10x + y = 10*3 + 6 = 36
@skb
Let us assume, x is a tenth place digit and y is the unit place digit of a two-digit number.
Therefore, the two-digit number = 10x + y and the reversed number = 10y + x
Given:
y = 2x -----------1
Also given:
10x + y + 27 = 10y + x
9y - 9x = 27
y - x = 3
Substitute the value of y from equation 1 in equation 2
2x - x = 3
x = 3
Therefore y = 2x = 2 * 3 = 6
Therefore, the two-digit number = 10x + y = 10*3 + 6 = 36
@skb
RabbitPanda:
Thnx 4 brainlist☺
Answered by
1
the two digit number is 36..
if we add 27 to 36 it will be 27+36=63 which is reverse of 36
if we add 27 to 36 it will be 27+36=63 which is reverse of 36
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