Question

in a 2-digit number, digits in units place is twice the digit in tens place. if 27 is added to it, digits are reversed. Find the number​

Answer 1

$\large\bold{\underline{\underline{\purple{➩given:-}}}}$

In a 2-digit number , digit's in unit's please is Twice the digit in tens Place . if 27 is added to it , digits are reserved.

$\large\bold{\underline{\underline{\purple{➩to \: find:-}}}}$

To find the another Number.

$\large\bold{\underline{\underline{\purple{➩solution:-}}}}$

• Let's the number at the unit place and tenths place digits be x' and 2x'.

Respectively and the number be 20x+x

Now,

= 20x + x -27=10x+2x

=21x -27 =12x

=9x=27

x'=3

Hence the number is 21×3=63

Answer 2

$\huge\sf{\underline{\underline{Answer}}}$

Given that:-

In a two digit number digit in units place is twice the digit in the tens place.

If 27 is added to it, the digits are reversed.

To find:-

The Number

________________________________________________

▪Let ten's digit = x  

▪Unit's digit = 2x

Required Number = 10x + 2x = 12x

On Interchanging the Digit's Number = 10 (2x) + x = 21x

According to the question

$\tt\bold{12x + 27 = 21x}$

$\tt\bold{27 = 21x - 12x}$

$\tt\bold{27 = 9x}$

$\tt\frac{27}{9} = x$

$\tt\bold{x = 3}$

12 × 3 = 36

•°• Required number is 36.