Question

In a 2 digit number the sum of the digit is 7. If the number with order of the digits reversed is 28 greater than twice the unit's digit of original number . Find the number.​

Answer 1

Answer:

43

Step-by-step explanation:

let the original number be 10(7-x)+x

here ,x is the one's digit and (7-x) is the ten's digit which is why we multiply it with 10.

the reversed number would be 10x +(7-x)

we know that

10x+(7-x)=28+2x

10x+7-x=28+2x

7x=21

x=3

hence the original number is

10(7-3)+3

=43

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Answer 2

Answer:

43

Step-by-step explanation:

Let the digits be x(ten's digit) and y(unit's digit)

x+y = 7 ----- (1)

Original number = 10x+y

Reversed number = 10y + x

10y+x = 2y+28

x+8v=28  ---- (2)

Subtract (2)  - (1)

7y = 21

y = 3

x= 4

Original number = 43

Reversd number = 34