Question

in a 2-digitnumber,the face value of the digit at the tens place is four times that of the digit at one's place.if 54 is subracted from the number ,the digits are reversed.find the number. (after finding the number check that LHS=RHS)

Answer 1

Let the digits be 'ab'
That is 'a' in tens place and 'b' in ones place.
The no. Is 10a+b as in expanded form
When 54 is subtracted the digits are reversed
That means the digits will be 'ba' :'b' in tens place and 'a'in ones place
So the no. Can be written as 10b+a as in expanded form
According to the condition
10a+b -54 = 10b+a
=>9a -9a-54 = 0
=>a-b-6=0
=>a-b = 6 ------------(1)

Also given that the first digit is 4 times the second
=> a= 4b
Substituting in (1)

4b-b=6
=>3b=6
=>b =2
=> a= 8
Therefore the no.is 10a+b = 10(8)+2 = 82

Answer 2

Phala answer thik ha Aap yisa Kar loo