in a 2digit number the sum of two digit number is 9 if 27 is added to a number the digits are reversed find the number
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36 sum is 9and adding 27 it becomes 63
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let the digit at ones place be = y
let the digit at tenth place be = x
so,
x+y=9. [GIVEN]
x = 9-y. [EQUATION 1]
the original number is 10x+y
So reversed number is 10y+x
10x+y+27=10y+x
putting values of x from equation1 in above
On solving y=6
x=3
So number is 36
let the digit at tenth place be = x
so,
x+y=9. [GIVEN]
x = 9-y. [EQUATION 1]
the original number is 10x+y
So reversed number is 10y+x
10x+y+27=10y+x
putting values of x from equation1 in above
On solving y=6
x=3
So number is 36
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