Question

In a 3 digit number, if the digit in the hundredth place is 3 more than the digit in the tens place and the digit in the units place is four more than the digit in the tenth place, Find the three digit number given that sum of digits of the number is 10? ​

Answer 1

Answer:

Step by step explanation:

Let the digit in ten's place be x.

Then, the digit in the hundred's place =

3

x

and digit in the unit's place = 4×

3

x

=

3

4x

∴ The original number = 100×

3

x

+10×x+

3

4x

=

3

100x

+10x+

3

4x

=

3

100x+30x+4x

=

3

134x

In the new number,

Digit in the ten's place =

3

4x

Digit in the unit's place =x

Digit in the hundred's place =

3

x

100×

3

x

+10×

3

4x

+x=

3

100x+40x+3x

=

3

143x

Given,

3

143x

−

3

134x

=18

⇒

3

9x

=18

⇒x=6

∴ Original number =

3

134

×6=268

∴25% of 268=

100

25

×268=

4

268

=67