Question

in a 3 digit number sum of digits is 9and the units digit is twice the tens digit on adding 99 to the number the digits are reversed find the no

Answer 1

let the 3 digit number be xyz

their sum x+y+z = 9

units digit number is z = 2y --------(1)

if 99 is added => 100x + 10y + z + 99 = 100z + 10y + x

100z + 10y + x - 100x - 10y - z = 99

99z - 99x = 99

99(z - x) = 99

z - x = 99/99

z - x = 1

z = 1 + x

2y = 1 + x

y = (1 + x)/2

(1 + x) + (1 + x)/2 + x = 9

2(1+x) + (1+x) + 2x = 18

2+2x+1+x+2x = 18

5x+3 = 18

5x = 18 - 3

5x = 15

x = 15/5

x = 3

z = 1 + x = 1 + 3 = 4

2y = 1 + x

2y = 1 + 3

2y = 4

y = 4/2

y = 2

hence the number is 324

Answer 2

Answer:

hence the answer is 324

Step-by-step explanation:

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