In a ||5m ABCD, if A = 115°, then
ZB, LC and LD are respectively of -
65°, 65°, 115
65°, 115°, 65°
65°, 65°, 130
65°, 1150, 65°
Answers
Answered by
21
Answer:
,Let ABCD be a parallelogram in which ∠A=65
∘
.
Since AD∥BC we can treat AB as a transversal. So,
∠A+∠B=180
∘
65
∘
+∠B=180
∘
∠B=180
∘
−65
∘
∠B=115
∘
Since the opposite angles of a parallelogram are equal, we have
∠C=∠A=65
∘
and ∠D=∠B=115
∘
Hence, ∠B=115
∘
,∠C=65
∘
and ∠D=115
∘
solution
Answered by
0
Step-by-step explanation:
Let ABCD be a parallelogram in which ∠A=65
∘
.
Since AD∥BC we can treat AB as a transversal. So,
∠A+∠B=180∘
65∘ +∠B=180∘
∠B=180∘
−65 ∘
∠B=115 ∘
Since the opposite angles of a parallelogram are equal, we have
∠C=∠A=65∘
and ∠D=∠B=115∘
Hence, ∠B=115
∠C=65⁰
and ∠D=115⁰
hope it is helpful
Similar questions
English,
2 months ago
World Languages,
2 months ago
CBSE BOARD XII,
2 months ago
Geography,
5 months ago
Computer Science,
5 months ago
Math,
10 months ago
Math,
10 months ago
Math,
10 months ago