In a 729 litres mixture of milk and water, the ratio of milk to water is 7:2. to get a new mixture containing milk and water in the ratio 7:3, the amount of water to be added is:
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Answered by
4
Hey.
Here is the answer.
As, 729 L mixture has 7 :2 of milk & water,
so, milk = 729×7/9 = 567 L
and, water = 729×2/9 =162 L
As, in the new mixture the ratio is 7 : 3 but only water is added, amount of milk will remain unchanged (567L ) .
Let total amount of new mixture = x L
so, milk = x × 7/10 = 567 L
or, x = 567×10/7 = 810 L
So, new volume 0f water = 810-567=243 L
Hence water to be added = 243 - 163 L = 80L
Thanks.
Here is the answer.
As, 729 L mixture has 7 :2 of milk & water,
so, milk = 729×7/9 = 567 L
and, water = 729×2/9 =162 L
As, in the new mixture the ratio is 7 : 3 but only water is added, amount of milk will remain unchanged (567L ) .
Let total amount of new mixture = x L
so, milk = x × 7/10 = 567 L
or, x = 567×10/7 = 810 L
So, new volume 0f water = 810-567=243 L
Hence water to be added = 243 - 163 L = 80L
Thanks.
Answered by
2
Answer:81
Explanation: total mixture is :- 729
Ratio of milk to water is :- 7:2=9
Now
(729/9)×7=567 milk
Water is 729-567=162
567/(x+162)=7/3
567×3=7(x+162)
1701=7x+1134
7x=567
X=81 litter water
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