In a AABC, ZB = 90° AB = 24cm and BC = 7cm, find sinC.
sinC =
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Answer:
In ∆ABC,
ZB = 90°
l(AB) = 24cm
l(BC) = 7cm
In ∆ABC = 90°,
By Pythagoras theorem,
√AC = 576 + 49
√AC = 527
AC = √625
AC = 25cm
sin C = Opposite side/Hypotenuse
sin C = AB/AC
sin C = 24/25
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