Question

In a ∆ABC , 2 ∆A =3 ∆b =6∆c. Calculate ∆A , ∆B, ∆C.

Answer 1

Answer:

angle A=90°

angle B = 60°

angle C= 30°

Step-by-step explanation:

angle A+angle B+angleC=180......(1)

by angle sum property of triangle

since angle 2A=3B=6C

A=3C

B=2C

by putting it in (1)

3C+2C+C= 180

6C=180

C=30°

now

A=3C

=3x30

=90°

B=2C

=2x30

= 60°