In A ABC, AD and BE are medians on sides BC and AC respectively. If angle DAC = CBE = 30° show that A ABC is an equilateral triangle.
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In triangles ADB & ADC
AD is median to BC (given)
=> BD = CD
& AD perpendicular to BC ( given)
=> <ADB = < ADC = 90°
& AD = AD ( common to both triangles)
=> tri ADB congruent to tri ADC ( by SAS congruence rule)
=> AB = AC ( csct)
Similarly, we can prove tri BEA congruent to tri BEC ( by SAS)
=> AB = CB ( csst)
This way AB = BC = AC
=> tri ABC is an equilateral triangle.
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