Question

In a Δ ABC, AD bisects Δ A and ΔC > ΔB. Prove that ΔADB > ΔADC.​

Answer 1

Answer:

Given: AC = AB

           AD bisects BC

To Prove: ΔADC ≅Δ ADB

Proof:

In ΔADC and ΔADB

1. AB = AC  -------------  Given

2. BD = DC -------------( As AD bisect BC, given)

3. AD = DA -----------( Common side)

∴ ΔADC≅ ΔADB by SSS test

   Hence proved

Answer 2

Answer:

in congruent angle

AD=AD (COOMON)

ANGLE ABC=ADC (ANGLE)

AB=AD(SIDE)

SO PROVED THAT

ADB