Question

IN a ∆ABC . AD is perpendicular to BCand AD^2=BD×CD. Prove that∆ABC is a right angled triangle

Answer 1

in Triangle Adb and Triangle Adc AD perpedicular to BC
By proving similarity
angle ADC=angle ADB =90degree
angle ABC =angle ADC

By AA criteria
triangle CDA is similar ADB

CD/AD=AD/BD=DC/BA
AD
$ad ^{2}$

Answer 2

Answer:

Check your answer please