in a ∆ ABC , angle A =45°,angle b=70°. name the shortest side and find angle c
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Answer:
Therefore BC is the shortest side
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I well to brainly .
Let c° = teta.
We know that,
Sum of angles of triangle is 180°.
A+B+C =180.
45°+70°+C=180°
135°+C=180°
C=180-135
C= 45°
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