Question

in a ∆ abc ,angle abc=angle acb and the bisectors of angle abc and angle acb intersect at o such that angle boc =120°. show that angle a=angle b= angle c =60°

Answer 1

since bisector divides the angle in equal part
since angle obc=angle=ocb
then angle obc+angle ocb +angle boc =180degree
since angle b = angle c
isliye angle obc = angle ocb =30degree(by angle sum property)
then angle b and c are double of 30 equal to
60 degree
then by angle sum property angle a=60
prove
sorry because i did not solve on the paper