Question

In a ∆ ABC , angle c = 3anglec=2( angle A+ angle B) find the three angle​

Answer 1

Answer:

We know Angle A+B + C = 180°

so ,. Multiplying by 3

we get,. 3A + 3 B +3C = 540°

3A + 3B + (2A+ 2B) = 540

5A + 5B = 540

5 ( A+ B ) = 540/ 5

A + B = 108

C = 180 - 108

C = 72°