Math, asked by ScientistKhushi, 1 year ago

In a ∆ ABC, angleA = x
angle B = 3x
angle C= y
. If 3y – 5x = 30, prove that the triangle is right angled.

Answers

Answered by chiefLucky

3y-5x=30
3y=30+5x
y=30+5x/3
ATQ,

x+3x+y=180°
4x+(30+5x/3)=180°
(12x+30+5x)/3=180°
17x+30=540
17x=540-30
17x=510
x=510/17
x=30

Therefore the three angles=30°, (3x)=90°, and (30+5x/3=30+5(30)/3=180/3)=60°
Since one of the angles is 90°, hence proven that the triangle is a right triangle.
Plz mark as brainliest

ScientistKhushi: Thank u very much... ^_^ I can't mark it brainliest because no one else has answered yet.

chiefLucky: Okay

chiefLucky: No problem

chiefLucky: Lets wait

ScientistKhushi: Hmm.... I'll mark urs as brainliest

chiefLucky: Thx

ScientistKhushi: What is ATQ in the answer?

chiefLucky: According to Question

ScientistKhushi: ok thanks

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In a ∆ ABC, angleA = xangle B = 3xangle C= y. If 3y – 5x = 30, prove that the triangle is right angled.

Answers

In a ∆ ABC, angleA = x
angle B = 3x
angle C= y
. If 3y – 5x = 30, prove that the triangle is right angled.