Question

In A ABC, angleB= 90° and BD is an altitude.
If BD = 2CD, prove that AC = 5CD.​

Answer 1

Step-by-step explanation:

According to property associated with Altitudes in Right Angled Triangle

The Altitude to Hypotenuse Divides the triangle into 2 Similar triangles

⟹ΔADC≈ΔCDB

So

AD

CD

=

CD

BD

⟹CD

2

=BD×AD