Question

In a Δ ∠ ABC B , = 90° and AB = 4 cm, BC = 3 cm and AC = 5 cm. Find sinA​

Answer 1

Step-by-step explanation:

$\sin(a) = \frac{ab}{ac} = \frac{4}{5}$

Answer 2

GIVEN:

• Angle B=90°
• AB=4cm
• BC=3cm
• AC=5CM

TO FIND:

• Sin A

SOLUTION:

$\large\sf Sin \: A = \frac{P}{H}$

Note⇝For Sin A perpendicular will be 3cm

$\large\sf \: \: \underline{ \boxed{ \sf \: \blue{Sin \: A = \frac{3}{5}}}} \: \: \huge \checkmark$

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$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\tt Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \tt\angle A & \bf{0}^{ \circ} & \tt{30}^{ \circ} & \tt{45}^{ \circ} & \tt{60}^{ \circ} & \tt{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}$