Question

In a ∆ABC, D,E,F are midpoints of BC, CA, AB. Show that BDEF is a llgm and ar(∆DEF)=1/4ar(∆ABC)​

Answer 1

Step-by-step explanation:

According to mid point theorum

FE || to BC and

FE=1/2 BC

FE||BC and FE=BD

=> BDEF is a paralleogram

To prove= ar(DEF)=1/4ar ABC

BDEF is a parallelogram

DEFC is a paralleogram

AFDE is a paralleogram

=> ar(ABC)=4x

=ar(DEF)=x

=Ar(DEF)=1/4 ar(ABC)

Hope it helps

Answer 2

Step-by-step explanation:

ggggg2tfdetujsqwugsrvtvtbt3hu