In a ∆ABC, if 2angle equals to 3 angle b equal to 6 angle c calculate angle a angle b and angle c
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Answer:
a=90°, b=60° and c=30°
Explanation:
2a=3b=6c
(i) a = 3b/2
(ii) c = 3b/6 = b/2
SO, In ΔABC
⇒ a + b + c=180°
or, 3b/2 + b + b/2= 180° [∵From EQn (i) and (ii)]
or, 3b + 2b + b = 180° × 2 [∵Taking LCM on LHS and taking 2 to the RHS]
or, 6b = 360°
∴ b = 60°
⇒ a = 3b/2 = (3×60°)/2 = 90°
⇒ c = b/2 = 60°/2 = 30°
Thus,
In ΔABC, ∡a = 90°
∡b = 60°
∡c = 30°
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