Question

In a ∆ABC if 3<A=4<B=6<c, calculate the angles.
please solve the question​

Answer 1

Answer:

3A=4B=6C Therefore B= 3/4*A and C=3/6*A A+ (3/4*A)+ (3/6*A) = 180 (12A + 9A + 6A)/ 12= 180 27A/12 = 180 A= (180*12)/27 A= 80 B= 60 C= 40 Note: All the figures are in degrees.

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Answer 2

Answer:

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