Question

In a∆ABC if bSinc(bcosC+CCosB)=42 Find Area of ∆ABC​

Answer 1

$\huge{\underline{\tt{\blue{Answer}}}}$

Given:

bSinC(bCosC+cCosB) =42

$\huge{\underline{\tt{SoluTion}}}$

$\implies bsinC \times a = 42 \\ \\ \implies absinC=42 \\ \\ Area\:Of\:Triangle= \dfrac{1}{2} \times abSinC$

$\therefore$ AREA OF triangle will be 21

Answer 2

Question

In a∆ABC if bSinc(bcosC+CCosB)=42 Find Area of ∆ABC

Answer

refer to the attachment

hope it helps you