In a ABC, if3A=4B=6C, calculate the angles
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Answer:
A = 80 , B = 60 , C = 40
Step-by-step explanation:
Here 3A = 6C =4B
so , A = 2C
also A = 4/3 B
now in triangle ABC
A + B + C = 180 ( sum of angle of triangle = 180 )
= A + 3A/4 + A/2 = 180
= 4A +3A +2A = 180 × 4
= 9A = 180 × 4
= A = 180 × 4/9
A = 20×4
A = 80
now 3A= 4B
= 3× 80 /4 = B
therefore B = 60
again
3A = 6 C
= 3× 80 /6 = C
therefore C = 40 .
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