Question

In a ABC, if3A=4B=6C, calculate the angles

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Answer 1

Answer:

A = 80 , B = 60 , C = 40

Step-by-step explanation:

Here 3A = 6C =4B

so , A = 2C

also A = 4/3 B

now in triangle ABC

A + B + C = 180 ( sum of angle of triangle = 180 )

= A + 3A/4 + A/2 = 180

= 4A +3A +2A = 180 × 4

= 9A = 180 × 4

= A = 180 × 4/9

A = 20×4

A = 80

now 3A= 4B

= 3× 80 /4 = B

therefore B = 60

again

3A = 6 C

= 3× 80 /6 = C

therefore C = 40 .