Math, asked by sudhakhari8213, 11 months ago

In a ΔABC , perpendicular AD from A on BC meets BC at D. If BD = 8 cm, DC = 2 cm and AD = 4 cm, then
A.ΔABC is isosceles
B. ΔABC is equilateral
C. AC = 2 AB
D. ΔABC is right-angled at A.

Answers

Answered by arsh122100
7

Answer:In a ΔABC , perpendicular AD from A on BC meets BC at D. If BD = 8 cm, DC = 2 cm and AD = 4 cm, then

A.ΔABC is isosceles

B. ΔABC is equilateral

C. AC = 2 AB

D. ΔABC is right-angled at A.

Step-by-step explanation:

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Answered by Studioussubi2006
0

ΔABC is isosceles

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