In a right triangle ABC right-angled at B, if P and Q are points on the sides AB and AC respectively, then
A. AQ² + CP² = 2 (AC²+ PQ²)
B. 2 (AQ² + CP²) = AC² + PQ²
C. AQ² + CP² = AC² + PQ²
D. AQ + CP=(1/2)(AC + PQ).
Answers
Answered by
2
Answer:
Option c............is the correct
Answered by
7
Answer:
Hi again....
c is correct
AQ² +CP² = AC²+PQ².
AP² +PQ²+BP²+BC² =AC² +PQ².
AGAIN,AP² +BP² +BC²=AC².
AB²+BC²=AC².
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