Question

In A ABC, PQII BC and BD = DC.
Prove that PE=EQ,​

Answer 1

Answer:

because BD=DC there fore PQ\\BC therefor PE=EQ

Answer 2

In Triangle ABC, PQ || BC and BD = DC.

We know that AD bisects PQ and PE = EQ

We also know that PE || BD and EQ II DC

But, it is given that BD = DC, therefore,

$\implies$PE II EQ

(Because if two or more lines are parallel to the same line then they are parallel to each other)

Hence, PE II EQ.