In a ∆ ABC, right angled at B, if AB = 4 and BC = 3 find all the six t - ratios of ∆A
Answers
Answered by
1
We have, AB = 4 and BC = 3.
By Pythagoras theorem, we have
AC
2
=AB
2
+BC
2
⇒AC=
AB
2
+BC
2
⇒AC=
4
2
+3
2
=
25
=5
When we consider the t-ratios of ∠A, we have
Base = AB = 4, Perpendicular = BC = 3, Hypotenuse = AC = 5.
∴sinA=
AC
BC
=
5
3
,cosA=
AC
AB
=
5
4
,tanA=
AB
BC
=
4
3
Answered by
0
Answer:
We have, AB = 4 and BC = 3.
By Pythagoras theorem, we have
AC² =AB² +BC²
⇒AC= AB²+BC²
⇒AC= 2 +3 = 25
4 2
=5
When we consider the t-ratios of ∠A, we have
Base = AB = 4, Perpendicular = BC = 3, Hypotenuse = AC = 5.
∴sinA= BC
AC
= 3
5
,cosA= AB
AC
= 4
5
,tanA= BC
AB
= 3
4
Similar questions