in a∆ABC right angled at C,if tanA=1/√3,find the value of sinA cosB+cosA sinB
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Answer:
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Step-by-step explanation:
Given that,
tanA = 1/√3
A= 30° , B=60°
sinA=1/2
cosB=1/2
cosA=√3/2
sinB=√3/2
On solving,
(1/2*1/2)+(√3/2*√3/2)
1/4+3/4=1
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