in a ap if twelth term is -13 and sum of four first term is 24,find thebsum of first 10 terms
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Step-by-step explanation:
Given , a12=-13
S4=24
Wkt
An = a+ (n-1)d
-13= a +11 d
a=-13-11d-----(1)
Also , sn = n/2 ( 2a+(n-1)d)
24=2(2a+3d)
12=2a+3d ---(2)
Putting a's value from (1) in (2)
12 = -26-22d+3d
12+26=-19d
38=-19d
d=-2----(3)
Putting value of d's in (1)from (3)
a=-13-11(-2)
a=-13+22
a=9
Sum of first 10 terms be :
S10= 5(18+-18)
S10 = 0
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