In Δ A B C , ∠ A B C = 90 ° . A D is the median to B C and C E is the median to A B . If A C = 34 m and A D = 2 √ 241 m , find C E . Give your answer in surd form.
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Answered by
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Hlw mate!!
Since AD is the median of ΔABC, then BD = DC.
Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem,
it bisects the third side which in this case is AC at E.
Therefore, E is the mid point of AC.
Hence, BE is the median of ΔABC.
Hope it helpful
Since AD is the median of ΔABC, then BD = DC.
Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem,
it bisects the third side which in this case is AC at E.
Therefore, E is the mid point of AC.
Hence, BE is the median of ΔABC.
Hope it helpful
Anonymous:
thank u for reporting my before answer.
Answered by
3
Answer:
BE
Step-by-step explanation:
Since AD is the median of triangleABC
then sides BD = DC.
Given, DE parallel to AB
DE is drawn from the mid of BC
i.e. , D, then by convert of mid-point theorem.
it bisecting the third side.
∴ E is the mid point of AC.
so, BE is the median of triangleABC.
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