Math, asked by ManojKumarMansingh, 7 days ago

In a bag contains total number of 84 coins of 50 paisa and 25 paisa and 20 paisa and 10 paisa available in a bag then what is the amount of each coin respectively?​

Answers

Answered by rameshrajput16h
1

Answer:

A bug contain coin 50 paise, 25 paise, 20 paise

& 10 paise in ratio 1:2:4:8 respectively.

→ Assume bag contain x coin.

So, 50 paise = x coin

25 pasie = 2x coin

20 paise = 4s coin

10 paise = 8x coin

→ total amount in bag = 52 Rs

So, 527 = 5200 paise

→ let,

∴50×x+25×2x+20×4x+10×8x=5200

∴260x=5200

∴x=20 coin

→20paise,

coin for 20 paise =4×x

=4×20

=80

So, the Ans is 80.

Similar questions