In a bag contains total number of 84 coins of 50 paisa and 25 paisa and 20 paisa and 10 paisa available in a bag then what is the amount of each coin respectively?
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Answer:
A bug contain coin 50 paise, 25 paise, 20 paise
& 10 paise in ratio 1:2:4:8 respectively.
→ Assume bag contain x coin.
So, 50 paise = x coin
25 pasie = 2x coin
20 paise = 4s coin
10 paise = 8x coin
→ total amount in bag = 52 Rs
So, 527 = 5200 paise
→ let,
∴50×x+25×2x+20×4x+10×8x=5200
∴260x=5200
∴x=20 coin
→20paise,
coin for 20 paise =4×x
=4×20
=80
So, the Ans is 80.
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