In a bag of 10 balls which contain 3 black,4 white,3red balls without replacement.how can we take out 1 black, 1 white,1 red from 10 balls
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In a bag of 10 balls which contain 3 black,4
white,3red balls without replacement.how can we take out 1 black, 1
white,1 red from 10 ballsA bag contain balls = 10
in black = 3
in white =4
in red =3
We take out 1 black 1 white & 1 red from 10 balls = there will be 7 balls
after taking balls = 2 are in black , 3 are in white & 2 are in red
in black = 3
in white =4
in red =3
We take out 1 black 1 white & 1 red from 10 balls = there will be 7 balls
after taking balls = 2 are in black , 3 are in white & 2 are in red
narminnishana:
Wot is t answer...can u plz send with correct steps
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number of black balls = 3
number of ways in which 1 black balls can be taken = ³C₁ = 3
number of white balls = 4
number of ways in which 1 white balls can be taken = ⁴C₁ = 4
number of red balls = 3
number of ways in which 1 red balls can be taken = ³C₁ = 3
so total number of wasy = ³C₁ × ⁴C₁ × ³C₁ = 3×4×3 = 36
number of ways in which 1 black balls can be taken = ³C₁ = 3
number of white balls = 4
number of ways in which 1 white balls can be taken = ⁴C₁ = 4
number of red balls = 3
number of ways in which 1 red balls can be taken = ³C₁ = 3
so total number of wasy = ³C₁ × ⁴C₁ × ³C₁ = 3×4×3 = 36
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