in a bag there are 20 kg of fruits. if 43/6 of these fruits be orange and 26/3 kg of these are apples and rest are grapes. find the mass of the grapes in the bag
Answers
Answered by
61
20kg=43/6+26/3+x
43/6+52/6+x
(43+52)/6+x
95/6+x
15.8+x
20kg-15.8kg =x
4.2kg=x
43/6+52/6+x
(43+52)/6+x
95/6+x
15.8+x
20kg-15.8kg =x
4.2kg=x
Answered by
98
Solution:-
Let the quantity of grapes is 'x' kg.
So, according to the question.
x/1 Kg + 43/6 kg + 26/3 kg = 20 kg
Taking L.C.M. of the denominators and then solving it, we get.
(6x + 43 + 52)/6 = 20
6x + 95 = 20*6
6x = 120 - 95
6x = 25
x = 25/6 Kg
So, the grapes are 25/6 kilograms.
Or, 4.166 kg
Answer
Let the quantity of grapes is 'x' kg.
So, according to the question.
x/1 Kg + 43/6 kg + 26/3 kg = 20 kg
Taking L.C.M. of the denominators and then solving it, we get.
(6x + 43 + 52)/6 = 20
6x + 95 = 20*6
6x = 120 - 95
6x = 25
x = 25/6 Kg
So, the grapes are 25/6 kilograms.
Or, 4.166 kg
Answer
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