Question

In a bag there are 44 identical cards with figure of circles, of which 9 are blue and rest are green and 20 squares of which 11 are blue and rest are green. One card is drawn from the bag at random. Find the probability that it has the figure of (i) square (ii) green colour (iii) blue circle and (iv) green square.

Answer 1

Answer:

this is the answer of this question

Answer 2

(i) Probability of a square = 5/16

(ii) Probability of a green card = 11/16

(iii) Probability of a blue circle = 9/64

(iv) Probability of a green square = 9/64

Step-by-step explanation:

Total number of outcomes = 44 + 20 = 64

Number of circles = 44

Number of blue circle = 9

Number of green circle = 44-9 =  35

Number of squares = 20

Number of blue squares = 11

Number of green squares = 9

(i) Probability of a square = 20/64 = 5/16

(ii) Probability of a green card = 44/64 = 11/16

(iii) Probability of a blue circle = 9/64

(iv) Probability of a green square = 9/64