In a bag, there are a certain number of toy-blocks with alphabets A, B, C and D written on them. The ratio of blocks A: B: C: D is in the ratio 4:7:3:1. If the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks, what is the number of ‘B’ blocks?
Answers
Answered by
74
The number of ‘B’ blocks are 350.
Given, the ratio of blocks of A,B,C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be 'x'.
So, toy blocks with alphabet A is 4x and,
toy blocks with alphabet B is 7x and,
toy blocks with alphabet C is 3x and,
toy blocks with alphabet D is x.
Again, the number of 'A' blocks is 50 more than the number of 'C' blocks.
As no. of 'A' and 'C' blocks are 4x and 3x respectively.
So,
4x = 50 + 3x
⇒ x = 50
Thus, the number of 'B' blocks is 7x = 7(50) = 350
350 is the required number.
Answered by
6
Answer
4x+7x+3x+1x=50
15x
=50
x=0.3
Step-by-step explanation:
Similar questions