Math, asked by chakshukishorer, 10 months ago

In a bag, there are a certain number of toy-blocks with alphabets A, B, C and D written on them. The ratio of blocks A: B: C: D is in the ratio 4:7:3:1. If the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks, what is the number of ‘B’ blocks?

Answers

Answered by GulabLachman
74

The number of ‘B’ blocks are 350.

Given, the ratio of blocks of A,B,C,D are in the ratio 4:7:3:1

Let us consider the common ratio to be 'x'.

So, toy blocks with alphabet A is 4x and,

toy blocks with alphabet B is 7x and,

toy blocks with alphabet C is 3x and,

toy blocks with alphabet D is x.

Again, the number of 'A' blocks is 50 more than the number of 'C' blocks.

As no. of 'A' and 'C' blocks are 4x and 3x respectively.

So,

4x = 50 + 3x

⇒ x = 50

Thus, the number of 'B' blocks is 7x = 7(50) = 350

350 is the required number.

Answered by RajasthanIndia
6

Answer

4x+7x+3x+1x=50

15x

=50

x=0.3

Step-by-step explanation:

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