Math, asked by joshinisathiyaprakas, 2 months ago

in a bag there are balls numbered 1 - 50 find the probability of getting an odd number,a perfect square,zero, multiple of 15​

Answers

Answered by nitikamurarka
1

Answer:

probability of odd no. 1/50

probability of a perfect sq no. is 7/50

Answered by VεnusVεronίcα
185

\large \bf Given:

In a bag, there are 1-50 numbered balls.

 \\

\large \bf To ~ find :

We have to find the following :

  • Probability of getting an odd number.
  • Probability of getting a perfect square.
  • Probability of getting zero.
  • Probability of getting multiple of 15.

 \\

\large \bf Solution:

  • Probability of getting an odd number :

Total no. of balls = 50

Odd numbers under 50 = 25

[1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49]

\bf P( odd \: number)= \frac{No. \: of \: balls \: with ~odd \: numbers}{Total \: no. \: balls}

\bf P(odd \: number) =  \frac{25}{50}

\bf P(odd  \: number)= \frac{1}{2} /0.5

  • Probability of getting a perfect square :

Total no. of balls = 50

Perfect squares under 50 = 7

[1, 4, 9, 16, 25, 36, 49]

\bf P(perfect~ square)= \frac{No. \: balls \: with \: perfect \: square \: number}{Total \: no. \: of \: balls}

\bf P(perfect \: square)= \frac{7}{50} /0.14

  • Probability of getting zero :

Total no. of balls = 50

No. of zeroes under 50 = 0

[They are numbered from 1-50, not 0-50]

\bf P(zero)= \frac{No. \: of \: balls   \: with\: zero}{Total \: no. \: of \: balls}

\bf P(zero)= \frac{0}{50}  /0

  • Probability of getting a multiple of 15 :

Total no. of balls = 50

No. of multiples of 15 under 50 = 3

[15, 30, 45]

\bf P(multiple \: of \: 15)= \frac{No. \: of \: balls \: with \: multiple \: of \: 15}{Total \: no. \: of \: balls}

\bf P(multiple \: of \: 15)= \frac{3}{50} /0.06

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\large \bf {Must \: remember:}

  • What are perfect squares ?

A perfect square is a number that is the square of an integer.

Examples :

  1. 4 is a perfect square (2²=4).
  2. 6 is not a perfect square because it can't be expressed as a square of any integer.

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