Question

In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is 30 rupees in all, how many 5 p coins are there?

Answer 1

Question : In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is 30 rupees in all, how many 5 p coins are there?

Step-by-step explanation:

Given :

Total money in bag = 30 rupees

The coins of 25 p, 10 p and 5 p are in the ratio of 1 : 2 : 3.

We know that :

In the bag, there are coins of 10 p and 5 p in the ratio of 1 : 2

So,

Let the no. of 10 p coins = x  

Let the no. of 10 p coins = x  Let the no. of 5 p coins = 2x  

Total money in the bag = Rs. 30

According To problem :

⇒ 10x/100 + ( 5 × 2x)/100 = 30

⇒ 20x = 30  × 100

⇒ x = (30/20) × 100

⇒ x = 1.5 × 100

       = 150

Therefore ,

No. of 10 p coins = x = 150

No. of 10 p coins = x = 150No. of 5 p coins = 2x = 300

Answer 2

Answer:

150 coins.

Step-by-step explanation:

Given Problem:

In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is 30 rupees in all, how many 5 p coins are there?

Solution:

To Find:

How many 5 p coins are there?

----------------

Method:

1 Rupee = 100 paise

30Rs = 3000 paise

25p : 10p : 5p = 1 : 2 : 3

25×x + 10×2x + 5×3x = 3000

60x = 3000

x = 50

25×50 = 1250

10×2×50 = 1000

5×3×50 = 750

Verification:

Sum of 1250,1000,750.

1250

1000

+ 750

_______

3000

750 is the number of paise which we got adding all the 5 paise coins

So number of 5 paise coins = $\frac{750}{5}$ = 150 coins.