Question

In a bag there are some rupees 5 and rupees 10 if there are 40 notes in all and in amounting it is rupees 300 then find each type of notes

Answer 1

$\Large{\bf{\underline{\underline{\red{Given}}}}}$

In a bag there are some rupees 5 and rupees 10 if there are 40 notes in all and in amounting it is rupees 300

$\Large{\bf{\underline{\underline{\red{To\:Find}}}}}$

Find the each type of notes

$\Large{\bf{\underline{\underline{\red{Solution}}}}}$

• Total number of notes = 40
• Total Amount = Rs. 300

★ Let Rs.5 note be x and Rs.10 note be y

*According to the given condition*

• x + y = 40 -------(i)
• 5x + 10y = 300 --------(ii)

Multiply (i) by 5 and (ii) by 1

• 5x + 5y = 200
• 5x + 10y = 300

Subtract both the equations

➡ (5x + 5y) - (5x + 10y) = 200 - 300

➡ 5x + 5y - 5x - 10y = -100

➡ -5y = -100

➡ y = 100/5 = 20

Put the value of y in eqⁿ (i)

➡ x + y = 40

➡ x + 20 = 40

➡ x = 40 - 20 = 20

${\underline{\boxed{\bf{\blue{Number\:of\:Rs.5\:note=20}}}}}$

${\underline{\boxed{\bf{\blue{Number\:of\:Rs.10\:note=20}}}}}$

Answer 2

Answer:

The number of rupee 5 is 20 and 10 rupee 10 notes is 20.

Given:

• In a bag there are some rupees 5 and rupees 10 notes, in total they are 40 notes in all.

• Total amount is rupees is 300.

To find:

• Each type of notes.

Solution:

Let number of 5 rupee notes be x and 10 rupee notes be y.

According to the first condition.

x+y=40...(1)

According to the second condition.

5x+10y=300

=>5(x+2y)=300

Dividing both sides by 5, we get

=>x+2y=60...(2)

Subtract equation (1) from equation (2)

x+2y=60

-

x+y=40

_______

y=20

Substitute y=20 in equation (1)

x+20=40

=>x=40-20

=>x=20

The number of rupee 5 notes is 20 and rupee 10 notes is 20.