in a hydraulic press,a force of 200N is applied to master piston of area 25cm .If the press is designed to produce a force of 5000N,determine; The area of the slave piston.
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Answered by
1
Answer:
625²
Explanation:
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Answered by
2
Answer:
Explanation:
This question is based on pascal's Law.
So By Pascal's Law
=
therefore =force on input piston =200N
= Force on output piston = 5000N
therefore after putting the values we get,
a) = (25x 5000)/200
= 625
b) area of the salve piston = = 625
so = 625/3.14 = 199
so r = = 14.10 cm
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