Question

In a ballistic demonstration, a police officer fires a bullet of mass 50g with a speed of 200 m/s on soft plywood of thickness 2cm the bullet emerges with only 10℅ of its initial kinetic energy. What is the emergent speed of bullet.​

Answer 1

Answer:-

Your Answer Is 63.2 m/s.

Explanation:-

See the ATTACHMENTS.

Answer 2

Given :-

In a ballistic demonstration, a police officer fires a bullet of mass 50g with a speed of 200 m/s on soft plywood of thickness 2cm the bullet emerges with only 10% of its initial kinetic energy.

To Find :-

Velocity

Solution :-

We know that

1 kg = 1000 g

50 g = 50/1000 = 0.05 kg

Now

KE = 1/2 × m × v²

KE = 1/2 × 0.05 × (200)²

KE = 1/2 × 0.05 × 40000

KE = 0.05 × 20000

KE = 1,000 J

Now

10% of KE

10/100 × 1000

1/10 × 1000

100 J

Now

Let the velocity be v

KE = 1/2 × m × v²

100 = 1/2 × 0.05 × v²

100 × 2 = 0.05 × v²

200/0.05 = v²

4,000 = v²

√4000 = v

63.24 = v

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