In a basket there are 10a+b fruits. (a≠0 and a>b).Among them '10b+a'fruits are rotten. The remaining fruits distributed to 9 persons equally. How many fruits are left over after equal distribution? How many fruits would each child get?
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Answer: a-b
Step-by-step explanation:
In basket there are 10a+b fruits
10b+a fruits are rotten.
By removing rotten fruits we get
10a+b-(10b+a)
10a+b-10b-a
9a-9b
9(a-b) fruits
This remaining fruits distributed to 9persons
9(a-b)/9
a-b
Each child will get a-b fruits.
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