Question

In a bg railway track a specified ruling gradient is i in 250. The horizontal curve of 3 on a gradient of 1 in 250 will have permissible gradient of

Answer 1

Given ruling gradient = 1/250 * 100 = 0.4%.

Grade compensation for B.G = 0.04 * 3 = 0.12.

The permissible gradient = 0.4-0.12 = 0.28 that is 1/357.

pls mark me brainliest........

pls bro.......pls...........

Answer 2

THe Given ruling gradient = $\frac{1}{250}$ * 100

                                             = 0.4%.

Grade compensation for B.G = 0.04 * 3

                                                 = 0.12.

The permissible gradient = 0.4-0.12

                                             = 0.28 which is $\frac{1}{357}$.