Question

in a bivariate data, the sum of square of difference the ranks of observation values of two variables is 30 and the rank correlation coefficient is 9/11. find the number of pairs?​

Answer 1

Answer:

ANSWER

P=1−6

n(n

2

−1)

∑di

2

0.6=1−

n(n

2

−1)

6×66

n(n

2

−1)

6×66

=0.4

n(n

2

−1)=

2

3

×66×10=990

n=10

10(10

2

−1)=10(99)=990

Answer 2

Concept

Correlation is a statistical technique for proving a connection or association between two variables. To put it another way, the correlation coefficient formula aids in determining the correlation coefficient, which assesses how closely two variables are related. The correlation coefficient is a mathematical tool used to quantify correlation.

Given

rank of observation Σdi²= 30

rank correlation coefficient (P)= 9/11

Find

calculate the number of pairs.

Solution

from the given data,

p = 1 ₋ 6Σdi²/n(n²₋1)

9/11 =1 ₋ 6×30/n(n²₋1)

9/11 =1 ₋ 180/n(n²₋1)

180/n(n²₋1) = 1 ₋ 9/11

180/n(n²₋1) = 2/11

n(n²₋1) = 180×11/2

n(n²₋1) = 990

990 = 90(99) = 10(100₋1) = 10(10²₋1)

n(n²₋1) = 10(10²₋1)

n = 10

hence, the number of pairs are 10.

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