Question

In a box, 3th/4 of the balls are red, 1th/6 balls are
white, and the rest are blue. If there are 3 blue
balls in the box find the red balls number ?

Answer 1

Answer:

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Answer 2

Answer:

The number of red balls present in the box is 27.

Step-by-step explanation:

Assumption,

Let the no. of red balls be 'x'.

Let the no. of white balls be 'y'.

Let the no. of blue balls be 'z'.

Given,

The number of red balls is 3/4th of the total balls in the box.

i.e. x = 3/4 × (x + y + z)...(1)

The number of white balls is 1/6th of the total balls in the box.

i.e. y = 1/6 × (x + y + z)....(2)

The number of blue balls present in the box is (z) = 3

To find,

The number of red balls (x)

Calculation,

Substituting z = 3 in equation (2)

y = 1/6 × (x + y + 3)

6y = x + y + 3

5y = x + 3

y = (x + 3)/5...(3)

Substituting z = 3 and equation (3) in equation (1)

⇒ x = 3/4 × (x + (x + 3)/5 + 3)

⇒ x = 3/4 × (x + x/5 + 3/5 + 3)

⇒ x = 3/4 × (6x/5 + 18/5)

⇒ x = 9x/10 + 27/10

⇒ 10x = 9x + 27

⇒ x = 27

Therefore, the number of red balls present in the box is 27.

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