in a box contains 10 bulbs 2 are defective what is the probability that among 5 bulbs chosen at random none is defective
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Total number of elementary events =
Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is
So,required probability = = 5/12.
Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is
So,required probability = = 5/12.
richa141:
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Answered by
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Total cases 10c 5
Probability --8c5 / 10c5
Solve and get answer
Mark as brainliest if helpful
Probability --8c5 / 10c5
Solve and get answer
Mark as brainliest if helpful
OK sorry I did it if bulbs are chosen all at a once
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