Question

In a box there are 10 non-defective and some defective bulbs. If the probability that a bulb selected at random from the box to be defective is 27 then find the number of defective bulbs.
PLS ANSWER

Answer 1

$[tex]\huge\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Answer}}}}}}}} \\ \large\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Your~answer↓}}}}}}}} \\ \small\bold\ \\ Number \: of \: non \: defective \: bulbs = 10 \\ </p><p>Let \: number \: of \: defective \: bulbs \: = x \\ </p><p>Total \: number \: of \: bulbs \: = 10 + x. \\ </p><p>Probability \: of \: getting \: defective \: bulb = \frac{2}{7} \\ so \: \frac{x}{x + 10} = \frac{2}{7} \\ 7x = 2x + 20 \\ 5x = 20 \\ x = 4.$

Answer 2

Answer:

this is correct...........