In a box there are 10 non-defective bulbs and some defective bulbs. If the probability that a bulb selected at random from the box to be defective is 2/7, then find the defective bulbs
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Answer:
X = 4
Step-by-step explanation:
Non defective bulb : A= 10
Defective bulb : B= X
n (s) = X+ 10 n (B) = X
n (A)= 10
P (B) = X /x+10 = 2/7 { given}
X/x +10 = 2/7
- 7x = 2x +20
- 5x =20
- X = 20/5
X = 4 ans
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