in a box there are 3 blue , 4 red and 5 green balls.What is the probability of picking up four balls such that there are 2 red balls and 1 ball each of blue and green?
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4- Green 5- Blue 3- Red
(i) Red in colour → total = 4+5+3=12
⇒123=41
(ii) not Green in colour:- means balls maybe blue or Red.
Blue + Red = 5+3=8 and total = 12
So : Answer is 128=32
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